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Post by sparkpowder on Sept 3, 2010 15:07:02 GMT
Here are the prices:
1 Ticket- 10 Dan-Balls
2 Tickets- 15 Dan-Balls
3 Tickets- 30 Dan-Balls
4 Tickets- 55 Dan-Balls
5 Tickets- 105 Dan-Balls
10 Tickets- 655 Dan-Balls
15+ Tickets- 755 Dan-Balls, 55 more Dan-Balls for every additional 1 ticket
Here are the prizes:
1 Number- 25 Dan-Balls
2 Numbers- 50 Dan-Balls
3 Numbers- 25 Dan-Balls off your next purchase of tickets
4 Numbers- 50 Dan-Balls off
5 Numbers- 100 Dan-Balls
6 Numbers- Jackpot [250 Dan-Balls and 250 Dan-Balls off]
When 100 tickets are purchased, I will double the prizes and give everyone half price off of tickets. There will be 6 numbers from 1 to 99. Here is how you would put in your numbers:
1 75 56 99 45 22
EDIT: Doubled the prizes and increased the prices by 5 Dan-Balls. I will not charge extra for any tickets purchased before the changes though.
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Post by Fringe Pioneer on Sept 3, 2010 15:27:40 GMT
Do matching combinations count, or does the permutation have to match?
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Post by sparkpowder on Sept 3, 2010 15:30:54 GMT
Do matching combinations count, or does the permutation have to match? Any number that matches the numbers I have, regardless of order, will be eligible to win. |
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Post by disabled on Sept 3, 2010 15:38:25 GMT
Dude, Karma is something given by others to you to show how your are recognized in the community. Karma is not something you should be able to gamble with.
If you want to get out of your negative karma value, then stop posting shit like this.
Consider you smited...
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Post by Artifact123 on Sept 3, 2010 15:38:53 GMT
I would like... 2 Tickets!
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Post by Fringe Pioneer on Sept 3, 2010 16:04:22 GMT
Hmm...I obviously did not read the thread. Well, let's change the winnings from karma, which should be earned through respect, to Dan-Balls, which can be earned in a variety of ways such as here.
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Post by nmagain on Sept 3, 2010 17:31:17 GMT
Give me 1 ticket.
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Post by sparkpowder on Sept 3, 2010 18:29:56 GMT
Here are the prices: 1 Ticket- 5 Dan-Balls 2 Tickets- 10 Dan-Balls 3 Tickets- 25 Dan-Balls 4 Tickets- 50 Dan-Balls 5 Tickets- 100 Dan-Balls 10 Tickets- 650 Dan-Balls 15+ Tickets- 750 Dan-Balls, 50 more Dan-Balls for every additional 1 ticket Here are the prizes: 1 Number- 10 Dan-Balls 2 Numbers- 25 Dan-Balls 3 Numbers- 25 Dan-Balls off your next purchase of tickets 4 Numbers- 50 Dan-Balls off 5 Numbers- 50 Dan-Balls 6 Numbers- Jackpot [175 Dan-Balls and 250 Dan-Balls off] When 100 tickets are purchased, I will double the prizes and give everyone half price off of tickets. There will be 6 numbers from 1 to 99. Here is how you would put in your numbers: 1 75 56 99 45 22 Based on the above, that will be 10 Dan-Balls, Artifact. And Nmagin, that will be 5 Dan-Balls. EDIT: Would you both please choose 6 numbers from 1 to 99? |
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Post by Artifact123 on Sept 3, 2010 19:18:41 GMT
7 64 37 18 50 49
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Post by nmagain on Sept 3, 2010 20:33:47 GMT
9 75 36 27 88 64
Edit:
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Post by Artifact123 on Sept 4, 2010 14:18:26 GMT
I now remember i had 2 tickets!
6 54 39 3 84 66
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Post by nmagain on Sept 4, 2010 15:49:06 GMT
I can't get the thought that this is shop a fraud outta my head.
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Post by disabled on Sept 4, 2010 16:00:59 GMT
What did you expect? Ok, first it was a very expensive way to buy karma, now its a very good way to loose DBs. Gambling means always loosing and is under strict control in many countries for a good reason.
This is an especially good example of a rip of. The normal lotteries has what, 49 numbers? This one has 99. And the prizes are just laughable.
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Post by sparkpowder on Sept 4, 2010 16:04:09 GMT
What did you expect? Ok, first it was a very expensive way to buy karma, now its a very good way to loose DBs. Gambling means always loosing and is under strict control in many countries for a good reason. This is an especially good example of a rip of. The normal lotteries has what, 49 numbers? This one has 99. And the prizes are just laughable. For one, I have General Veers to help me transfer Dan-Balls. Second, the prizes are coming out of the ticket profits. Third, why do you think this is a fraud, Nmaingin? |
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Post by disabled on Sept 4, 2010 16:32:31 GMT
For one, I have General Veers to help me transfer Dan-Balls. Second, the prizes are coming out of the ticket profits. Captain obvious huh? I didn't question where the DBs come from or how they reach their destination. I just said, that the chance to win are very slim. And the chance to win more then you invested is barely existent. The prizes are laughable, I mean come on. If 3 are right, you get no dan-balls at all, just 25 off your next game. On the contrary, 2 right gives you 25 DBs cash. 1 gives you 10, so 3 right should exceed 35 DBs by far. And a "jackpot" by the definition I know, is a pot that increases with every game played. And there is no way we can control you. You can just pick the numbers you want and nobody will know, if they are made up or random. You could even give someone 3 numbers right, because you don't have to pay them anything. Sorry, but this just looks like a rip off. |
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Post by Qwerty on Sept 4, 2010 20:24:25 GMT
Why exactly does three tickets cost 25 when one costs 5? Math problem!
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Post by sparkpowder on Sept 4, 2010 20:48:32 GMT
Why exactly does three tickets cost 25 when one costs 5? Math problem! Because I decided not to increase them by increments of 5. |
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Post by Fringe Pioneer on Sept 4, 2010 21:04:05 GMT
Total Possible Combinations, Not Permitting Repeating Numbers (NPR) = 99!/(6!(99-6)!) = 99!/(6!93!) = (99*98*97*96*95*94*93!)/(6!93!) = (99*98*97*96*95*94)/6! = 1120529256 Total Possible Combinations, Permitting Repeating Numbers (PR) = (6 + 99 - 1)!/(6!(99 - 1)!) = 104!/(6!98!) = (104*103*102*101*100*99*98!)/(6!98!) = (104*103*102*101*100*99)/6! = 1517381580 | Matches | Chance (NPR) | Tickets Needed | Chance (PR) | Tickets Needed | | m = 1 | P = 6 * 98! * 99!-1 | T = ceiling(P-1) = 17 | P = 6 * 99-1 | T = ceiling(P-1) = 17 | | m = 2 | P = 6 * 97! * 99!-1 | T = ceiling(P-1) = 1617 | P = 6 * 99-2 | T = ceiling(P-1) = 1634 | | m = 3 | P = 6 * 96! * 99!-1 | T = ceiling(P-1) = 156849 | P = 6 * 99-3 | T = ceiling(P-1) = 161717 | | m = 4 | P = 6 * 95! * 99!-1 | T = ceiling(P-1) = 15057504 | P = 6 * 99-4 | T = ceiling(P-1) = 16009934 | | m = 5 | P = 6 * 94! * 99!-1 | T = ceiling(P-1) = 1430462880 | P = 6 * 99-5 | T = ceiling(P-1) = 1584983417 | | m = 6 | P = 6 * 93! * 99!-1 | T = ceiling(P-1) = 134463510720 | P = 6 * 99-6 | T = ceiling(P-1) = 156913358234 |
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Post by disabled on Sept 4, 2010 21:21:21 GMT
Why exactly does three tickets cost 25 when one costs 5? Math problem! Hahahaha I didn't even notice that... And thanks GV for posting the math. Just to give hard numbers, you have a 6% chance to have 1 right and 0.06% chance to have 2 right. So if you buy 15 tickets (for 750DBs) on average you win <10 DBs. If thats not a fair game... |
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